2. In one neutralization experiment,solid sodium hydroxide is added to aqueous h

Question

2. In one neutralization experiment,solid sodium hydroxide is added to aqueous hydrochloric acid in a calorimeter to form water and a salt.

A. Write down the complete chemical equation for this reaction.

NaOH(s)+HCl(aq)-->NaCl(aq)+H2O(l)

B.This reaction happens in two steps, solid sodium hydroxide dissolves into water and delta H1 =50.0 kJ.In second step, the aqueous sodium hydroxide reacts with hydrochloric acid forming water and a salt with deta H2 of -2100 kJ. According to hess's law, calculate the enthalpy change of the whole reaction.

C. Write down the net ionic equations for both steps described in b.

I have A. right, but i do not know what to do on B. and C.

Explanation / Answer

B.This reaction happens in two steps, solid sodium hydroxide dissolves into water and delta H1 =50.0 kJ.In second step, the aqueous sodium hydroxide reacts with hydrochloric acid forming water and a salt with deta H2 of -2100 kJ. According to hess's law, calculate the enthalpy change of the whole reaction.

NaOH(s) ---> Na+(aq) + OH-(aq) H1 = 50 kJ/mol

Na+(aq) + OH-(aq) + HCl (aq) ---> NACl(aq) + H2O(l) H2 = -2100 kJ/mol

Apply hess law:

add both equations

NaOH(s) + Na+(aq) + OH-(aq) + HCl (aq) ---> Na+(aq) + OH-(aq) + NACl(aq) + H2O(l) H2 =50 -2100 kJ/mol = 1600 kJ

C. Write down the net ionic equations for both steps described in b.

The net ionic equations for both steps:

NaOH(s) ---> Na+(aq) + OH-(aq)

H+(aq) + OH-(aq) ---> H2O(l)

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