7. How many grams of sodium carbonate will react with25.5 ml of 0.300 M hydrochl

Question

7. How many grams of sodium carbonate will react with25.5 ml of 0.300 M hydrochloric acid?

Na2CO3 + HCl > NaCl + H20 + CO2 (unbalanced)

a. Determine the number of moles (mmoles) hydrochloric acid used.

b. Determine the number of moles (mmoles) of sodium carbonate reacted.

c. Determine the mass (grams) of sodium carbonate reacted.

8. How many grams of aluminum hyfroxide will react with 75.5 ml of 0.250 M sulfuric acid?

Al(OH)3 + H2SO4 > Al2(SO4)3 + H20 (unbalanced)

a. Detrmine the number of mole (mmoles) sulfuric acid used.

b. Determine the number of moles (mmoles) Aluminum hydroxide reacted.

c. Detrmine the mass (grams) of aluminum hydroxide reacted.

9. Consider the following solutions. Put in order according to the boiling points from highest point to lowest. (Hint: Colligative properties. Kb=0.52 C/m for water)

a. 0.1 M c6h12o6 b. 0.1 M CaCl2 c. 0.1 M NaCl

Explanation / Answer

7. How many grams of sodium carbonate will react with25.5 ml of 0.300 M hydrochloric acid?

Na2CO3 + HCl > NaCl + H20 + CO2 (unbalanced)

Balance equation

Na2CO3 + 2HCl --> 2NaCl + H2O + CO2

a. Determine the number of moles (mmoles) hydrochloric acid used.

Mmol = M*V = 0.3*25.5 = 7.65 mmol of HCl

b. Determine the number of moles (mmoles) of sodium carbonate reacted.

1 mol of Na2CO3 per 2 mol of acid, therefore expect half of 7.65 mmol

7.65/2 = 3.825 mmol of sodium carbonate

c. Determine the mass (grams) of sodium carbonate reacted.

MW of sodium carbonate = 105.9888

mass= mol*MW = 3.825 *10^-3 * 105.9888 = 0.4054 grams of Na2CO3

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