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1.What is the pH of 0.15 M HI and the pH of 0.15 M H 2 S? 2. An example of P in

ID: 905763 • Letter: 1

Question


1.What is the pH of 0.15 M HI and the pH of 0.15 M H2S?


2. An example of P in its maximum and minimum oxidation states is:

a)white phosphorus and red phosphorus

b)P4O10 and PH3

c)H3PO4 and Na3PO4

d)PH3 and Na3P

3.Match the following statements in Column A with the correct answer from Column B

A B

            Formed when hydrochloric acid reacts with sodium hydroxide O2

            Formed when potassium peroxide is heated                                       N2

            Formed when ammonium chloride is heated                                       Cl2

            Formed when calcium hypochlorite reacts with HCl                         CH3COOH

            Formed when sodium oxide reacts with water                                   HCl

                                                                                                                        H2                   

                                                                                                                        NaOH

                                                                                                                        NaCl

Explanation / Answer

1) pH of 0.15 M HI :

[H+] = 0.15 N (For monoprotic acids, Molarity and normality are equal)

pH = -log [H+]

= - log [0.15]

= 0.823

pH = 0.823

pH of 0.15 M H2S

[H+] = 0.15 M = 0.15x 2 N = 0.30 N ( For diprotic acids, Normality = Molarity x 2)

pH = -log [H+]

= - log [0.30]

= 0.522

pH = 0.522

2)

An example of P in its maximum and minimum oxidation states is:

a)white phosphorus and red phosphorus   b)P4O10 and PH3 c)H3PO4 and Na3PO4   d)PH3 and Na3P

Ans : b

Maximum oxidation state of P is +5 and minimum oxidation state is -3.

a) white phosphorus and red phosphorus

In both, oxidation state of P = 0

b) P4O10 and PH3

P4O10 : 4P+ 10 (-2) = 0

P = +5

PH3 : P + 3(+1) = 0

P = -3

c) H3PO4 and Na3PO4

  H3PO4 : 3(+1) + P + 4(-2) = 0

P = +5

Na3PO4 :

3(+1) + P + 4(-2) = 0

P = +5

d) PH3 and Na3P

PH3 : P + 3(+1) = 0

P = -3

Na3P : 3(+1) + P = 0

P = -3

3) a) when hydrochloric acid reacts with sodium hydroxide = NaCl will be formed

HCl + NaOH ----------> NaCl + H2O

b) when potassium peroxide is heated = O2 will be formed

2 K2O2 ------> 2 K2O + O2

c) when ammonium chloride is heated = HCl will be formed

NH4Cl -------------> NH3+HCl

d) when calcium hypochlorite reacts with HCl = Cl2 wil be formed

Ca(OCl)2 + 4 HCl ------------------> CaCl2 + 2 H2O + 2 Cl2

e)when sodium oxide reacts with water = NaOH will be formed.

Na2O + H2O -------------> 2 NaOH