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ilsly SRil: Using Concentration as a Conversion Factor 30 g NaCl 100 g 100 g NaC

ID: 905575 • Letter: I

Question

ilsly SRil: Using Concentration as a Conversion Factor 30 g NaCl 100 g 100 g NaCl 30 g solution lution 100 mL solution 5.0 mol HBr 1 L solution 8 mL ethanol 1 Concentration Given Unitsd 14 g fructose 8 mL ethanol Given UnitsRequired Conversion Factor Factor Desired Units 100 mL solution 100 mL solution 30% (m/m) NaCl solution grams of solution grams of NaCl 100 mL solution 8 ml solutiorn 14 g fructose 100 mL ethanol 8% (v/v) ethanol solution milliliters of solution milliliters of ethanol 30 g solution 1 L solution 5.0 mol HBr 100 mL ethanol 100 g solution 100 g NaCL 14% (nw) milliliters of of fructose solution solution 30 g NaCI 5.0 M HBr solution moles of HBr liters of solution 8 mL solution 100 mL, fructoseL HBr 14 g solution5.0 mol solution 5.0 mol solution 14 g solution 1 L HBr 100 ml fructose Hints MyAnswers." ubmit

Explanation / Answer

PArt A:

a) 30% m/m NaCl solution: use the conversion factor of 30 g NaCl/100 g sol to get the grams of NaCl.

b) 8 %v/v Ethanol solution: use the conversion factor of 8 mL Ethanol/100 mL sol to get the mililiters of ethanol.

c) 14% m/v fructose solution: use the conversion factor of 14 g fructose/100 mL sol to get the grams of fructose.

d) 5 M HBr solution: use the conversion factor of 1 L solution/5 moles of HBr to get the liters of solution.

Part B:

2K3PO4(aq) + 3MgCl2(aq) --------------> Mg3(PO4)2(s) + 6KCl(aq)