please show all your work! 2) You have a solution that contains 0.1 M Ag, 0.1 M
ID: 904532 • Letter: P
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please show all your work!
2) You have a solution that contains 0.1 M Ag, 0.1 M Cu2^+ and 0.1 M Ba^2+. You would like to separate these ions by precipitation. For quality purposes, the relative error must be below 0.1%, i.e., the precipitation of each ion must be complete (> 99.9%) and there must not be more than 0.1% (by weight) of one of the other ions in the precipitate. Explain your answer: nature of precipitate, pH, concentrations etc. Be quantitative in your answer. Note: at the end, you want one vial with > 99.9% of the silver, one with > 99.9% of the copper, and one with > 99.9% of the barium. (6 points)Explanation / Answer
The solution contains 0.1M Ag+, 0.1M Cu2+, 0.1M Ba2+. First this solution is treated with 0.1 M NaCl then all the Ag+ ions are precipitated as AgCl. Filter the precipitate and separate the precipitate from filtrate. Noe the filtrate is added to the 0.1M sodium sulfate solution then all the Ba2+ ions are precipitated as BaSO4, filter the precipitate and separate it. Now filttrate is treated with sodium sulfide the all the Cu2+ ions are precipitated as CuS. Filter the precipitate and separate it in vial. Now we have three ions in three vials.
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