Assuming an efficiency of 23.30%, calculate the actual yield of magnesium nitrat

Question

Assuming an efficiency of 23.30%, calculate the actual yield of magnesium nitrate formed from 120.5 g of magnesium and excess copper(II) nitrate

NOTE: the answer is not 772.3 either so I have no idea how to solve...

Question 12 of 12 Incorrec Map saplingeaning Assuming an efficiency of 23.30%, calculate the actual yield of magnesium nitrate formed from 120.5 g of magnesium and excess copper() nitrate. Mg+Cu(NO3)2 Mg(NO3)2+Cu Number 178.7 Previous 3 Give Up & View Solution Try Again Next Exit Explanation First calculate the theoretical yield: 1. Convert the mass of Mg to moles. 2. Find the corresponding moles of Mg(NO3)2 using the coefficients in the balanced chemical equation. 3. Convert the moles of Mg(NO3)2 to grams. The actual yield is 23.30% of the theoretical yield.

Explanation / Answer

Mg + Cu(NO3)2 --------------> Mg(NO3)2 + Cu

24 g of Mg forms 148.3 g Mg(NO3)2

120.5 of Mg forms 744.6 g Mg(NO3)2

But the efficiency is 23.3 % only,

Therefore, yield = 744.6 x 23.3 / 100 = 173.5 g

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