A soultion is prepared by mixing Mt moles of the salt MCl2 (which dissociates co
ID: 903148 • Letter: A
Question
A soultion is prepared by mixing Mt moles of the salt MCl2 (which dissociates completely to M^2+ +2Cl-) and Lt moles of the ligand HL in 1 L. The following reactions may occur:
M^2+ + L- <------>ML+ K=1.0x10^8 HL(aq) <------> L- + H+ Ka= 1.0x10^-5
a) Write a mass balance for the metal species.
b) Write a mass balance for the ligand species. c) write a charge balance
d) Suppose that Mt=Lt=0.1 M (exactly) and the pH is somehow fixed at 5.00. ( This means that the charge balance no longer applies.) Use the equilibria and the two mass balances to find the concentrations of ML+, M^2+, L-, and HL.
Explanation / Answer
ANSWER:
NOTE: The question has many parts. please break it into two questions, here we answer first three parts
MCl2 <--------------> M2+ + 2Cl- -------1
M2+ + L --------> ML+ ----------2
(a) MASS BALANCE
from equation (1) rate of production of 1/2Cl- = M2+
Or Cl- = 2M2+ ------(3)
M2+exista as ML+ and M2+
therefore M2+ = ML+ + M2+
Introducing value of M2+ in equation (3)
Cl- = 2{[M2+] + [ ML+]} Mass balance equation.
(b) HL(aq) <------> L- + H+
mass balance
H+ = L- -----------(4)
L- exista as L- and ML+
Introducing value of L- in (4)
H+ = L- + ML+ Mass balance
(C) Charge balance:
n1[C1] +n2[C2] + ...... = m1[A1] +m2[A2] +....
C's are concentration of positive ions and n= charge on ion
A's are concentration of negative ions and m =charge on negative ions.
For charge balance we must include water dissociatio
H2O <------> H+ + OH-
[H+] + 2[M2+] + [ML+] = [OH-] + [Cl-] + [L-]
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