The chromatogram below is for a solution containing a mixture of limonene and cy

Question

The chromatogram below is for a solution containing a mixture of limonene and cymene, two naturally-occurring compounds found in lemon peel.

Limonene and cymene are present in an unknown proportion, so enough chlorobenzene is added to make its concentration in the solution equal to 0.0025 M.

Given that chlorobenzene has the lowest boiling point, and cymene has the highest boiling point, use the provided information to calculate the concentration of limonene in the mixture in moles per liter.

Explanation / Answer

Area given for,

A (chlorobenzene) = 256

B (limonene) = 1878.6

C (cymene) = 582.7

Total area = 2717.3

Area %

A (chlorobenzene) = 100 x (256/2717.3) = 9.42%

B (limonene) = 100 x (1878.6/2717.3) = 69.13%

C (cymene) = 100 x (582.7/2717.3) = 21.44%

Total molar concentration of solution = 0.0025

So, molar concentration of each in M (moles/L),

A (chlorobenzene) = 0.0942 x 0.0025 = 2.35 x 10^-4 M

B (limonene) = 0.6913 x 0.0025 = 1.73 x 10^-3 M

C (cymene) = 0.2144 x 0.0025 = 5.36 x 10^-4 M

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