Step by Step: What is the formula weight of magnesium iodide? How many magnesium

Question

Step by Step:

What is the formula weight of magnesium iodide? How many magnesium ions are present in 5.23 Times 10^-4 mol of magnesium iodide? Enter your answer in scientific notation. How many iodide ions are present in 5.23 Times 10^'4 mol of magnesium iodide? Enter your answer in scientific notation. How many magnesium ions are present in 6.1 mg of magnesium iodide? Enter your answer in scientific notation. How many iodide ions are present in 6.1 mg of magnesium iodide? Enter your answer in scientific notation.

Explanation / Answer

1) Magnesium Iodide = MgI2

Thus, each mole of magnesium iodide contains 1 mole of Mg2+ ions

Thus, moles of Mg2+ ions in 5.23*10-4 moles of MgI2 = 5.23*10-4

Hence Mg2+ ions = moles*avagardro's number = (5.23*10-4)*(6.022*1023) = 3.15*1020

2) each mole of magnesium iodide contains 2 moles of I- ions

Thus, moles of I- ions in 5.23*10-4 moles of MgI2 = 2*5.23*10-4

Hence I- ions = moles*avagardro's number = (2*5.23*10-4)*(6.022*1023) = 6.3*1020

3) Molar mass of MgI2 = 278 g/mole

Thus, moles of MgI2 in 0.0061 g of it = mass/molar mass = 2.19*10-5

Hence number of Mg2+ ions = (2.19*10-5)*(6.022*1023) = 1.32*1019

4) number of I- ions = 2*(2.19*10-5)*(6.022*1023) = 2.64*1019

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.