Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Molarity NaOH .2 NH4Cl .2 HCl .2 NH3 .2 This amount was used for each trial. NaO

ID: 901960 • Letter: M

Question

Molarity

NaOH .2 NH4Cl .2

HCl .2 NH3 .2

This amount was used for each trial.

NaOH 50 mL NH4Cl 50 mL

HCl 50 mL NH3 50 mL

Reaction NaOH and HCl

Reaction NaOH and NH4Cl

Reaction HCl and NH3

Calculate the expected (theoretical)molar enthalpies for the reactions.

With these values demonstrate Hess’s Law by calculating the enthalpy ofreaction 3 and comparing it to value obtained from (reaction 1 – reaction 2).

Calculate the molar enthalpy associated with each of the trials

* Determine the heat of reaction, q, for each trial

* Convert volume quantities to mole quantities

* Determine the molar enthalpy for each trial in kJ/mol

Use the experimental values to verify that Hess’s Law

* If data is not consistent with Hess’s Law comment on anyexperimental parameter that may have skewed the result.

******Please provide a concise explanation, thank you.*********

Trial Initial NaOH final NaOH+HCl 1 21.12°C 34.83°C 2 21.38°C 34.74°C 3 21.35°C 34.81°C 4 21.59°C 35.00°C

Explanation / Answer

Molarity NaOH .2 NH4Cl .2 HCl .2 NH3 .2 This amount was used for each trial. NaO

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote