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This reaction takes place in a nickel-iron battery: 1Fe + 2NiO(OH) + 2H2O > 1Fe(

ID: 901002 • Letter: T

Question

This reaction takes place in a nickel-iron battery:

1Fe + 2NiO(OH) + 2H2O > 1Fe(OH)2 + 2Ni(OH)2.

a.Determine the mass of iron(II) hydroxide produced if 279 g Fe and 733.6 g NiO(OH) react.
b. Determine the limiting and excess reactant.

An alkaline battery produces electrical energy according to this equation: Zn + 2MnO2 + H2O > Zn(OH)2 + Mn2O3

a. Determine the mass of Zn(OH)2 produced if 25.0 g Zn and 30.0 g MnO2 are used.
b. Determine the limiting and excess reactant.

The compound calcium cyanamide (CaNCN) can be used as a fertilizer. To obtain this compound, calcium carbide is reacted with nitrogen at high temperatures. CaC2 + N2 > CaNCN + C

a. What mass of CaNCN can be produced if 480.0 g CaC2 reacts with 140 g N2?
b. Determine the limiting and excess reactants.
c. Determine how much excess you have.

Lithium reacts spontaneously with bromine to produce lithium bromide. Write if 25.0 g of lithium and 25.0 g of bromine are present at the beginning of the reaction,
a. Determine the balanced chemical equation.
b. Determine the mass of lithium bromide produced (theoretical yield).
c. Determine the limiting and excess reactant.
d. Determine the mass of excess reactant

Explanation / Answer

Chemical reaction:
Fe + 2NiO(OH) + 2H2O > Fe(OH)2 + 2Ni(OH)2

Molar masses (g/mol):
Fe, 55.845
NiO(OH), 91.69
Fe(OH)2, 89.84

Convert mass to moles:
ni = mi/Mi
n, moles number
m, mass of compound
M, molar mass

Solving:
Fe, 279 g -> 4.996 moles
NiO(OH), 733.6 g -> 8.001 moles

According to the chemical reaction, two mole of NiO(OH) react with one mole of Fe.

1 Fe ------ 2 NiO(OH)
? Fe ------ 8.001 NiO(OH)

8.001 moles of NiO(OH) reacts with 4.0005 moles of Fe.
This way, there is an excess reactant of iron, 0.9955 moles (55.5937 g Fe).
The NiO(OH) react completely, so is our limiting reactant.

Determine the mass of iron (ii) hydroxide:
mi = ni.Mi
n, moles number
m, mass of compound
M, molar mass

The moles of iron (ii) hydroxide produced are equal to the moles consumed of iron.
mFe(OH)2 = (1/2)8.001 mol . 89.84 g/mol
mFe(OH)2 = 359.405 g

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