Question one: How many moles of a gas will occupy a volume of 0.6098 L at a temp

Question

Question one: How many moles of a gas will occupy a volume of 0.6098 L at a temperature of 354.8 K and a pressure of 1559 torr ?

Question two: If 25.0 g of ammonia gas has a temperature of 10.6 C and a pressure of 584 mmHg , what is its volume?

Question three: A 165.5 L kiln is used for vitrifying ceramics. It is currently operating at 1091.0 C , and the pressure is 1.075 atm . How many moles of air molecules are within the confines of the kiln?

Question four:

A 24.20 L gas cylinder has been filled with 3.922 moles of gas. You measure the pressure to be 3.330 atm . What is the temperature inside the tank?

Express your answer numerically in degrees Celsius. [Pay attention to the number of decimal places you are allowed in your answer!]

Explanation / Answer

Question one: How many moles of a gas will occupy a volume of 0.6098 L at a temperature of 354.8 K and a pressure of 1559 torr ?

Apply ideal gas law

PV = nRT

n = (PV)/(RT)

P = 1559torr --> 1559/760 atm = 2.05 atm

n = (2.05*0.6098)/(0.082*354.8) = 0.04296 mol

Question two: If 25.0 g of ammonia gas has a temperature of 10.6 C and a pressure of 584 mmHg , what is its volume?

m = 25 g

MW = 17

n = mass/MW = 25/17 = 1.53 mol of NH3

T = 10.6C or 283.6 K

P = 584 mm Hg or 584/760 = 0.768 atm

Sustitute in ideal gas

PV = nRT

V = nRT/P = (1.53)(0.082)(283.6)/(0.768) = 46.3 L

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