help.... please Why is NaCl a neutral solution? What is the pH of the 1 M CH_3CO
ID: 899501 • Letter: H
Question
help.... please Why is NaCl a neutral solution? What is the pH of the 1 M CH_3COOH solution? Write a chemical reaction (including the physical states) between acetic acid and H_2O. Identify the conjugate acid/conjugate base pairs of the reaction. Calculate the [H^+] of this solution. What is the pH of the 1 M NaCH_3COO solution? (Notice that this is a salt.) Write the dissolution reaction of the salt. Write the equilibrium reaction of the salt. Is this an acidic, basic, or neutral salt? Calculate the Ka using the concentrations of the components in the species window. Calculate the Ka using the formula Kw = Ka Times Kb and the appropriate equilibrium constant from the appendices in your book. What is the pH of the 1.0 M NH_4Cl solution? What the dissolution reaction of the salt. Write the equilibrium reaction of the salt.Explanation / Answer
NaCl is a neutral solution because it is a salt of a strong acid and strong base
4) a) 2.37
b) CH3COOH + H2O -----> CH3COO- + H3O+
c) Acid and its conjugate base: CH3COOH and CH3COO-
Base and its conjugate acid = H2O and H3O+
d) CH3COOH + H2O ------> CH3COO- + H3O+
1 - X .........................................X.................X
Ka = 1.8 x 10^-5 = X^2 / 0.1 - X
=> X = 4.27 x 10^-3 M = [H3O+] = [H+]
5)
a) Kb for CH3COO- = 5.5 x 10^-10
CH3COO- + H2O -----> CH3COOH + OH-
1 - X.....................................X.................X
Kb = 5.5 x 10^-10 = X^2 / 1 - X
=> X = 2.34 x 10^-5 M = [OH-]
=> pOH = 4.63
=> pH = 14 - pOH = 9.37
b) CH3COONa + H2O -----> CH3COOH + OH- + Na+
c) CH3COONa + H2O <-----> CH3COOH + OH- + Na+
d) Solution is Basic
6)
b) NH4Cl + H2O -----> NH3 + H3O+ + Cl-
c) NH4Cl + H2O <-----> NH3 + H3O+ + Cl-
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