SYNTHESIS OF TRIS(ETHYLENEDIAMINE)NICKEL(II) CHLORIDE- Post Lab Questions. Why i
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SYNTHESIS OF TRIS(ETHYLENEDIAMINE)NICKEL(II) CHLORIDE- Post Lab Questions.
Why is it specified that only a minimum amount of water be used to dissolve NiCI2-6H20? Carefully explain how using more than a minimum amount would a your results. The procedure calls for using between 0.500 to 0.650 g of the hydrate in the synthesis. Would a student using 0.500 g of hydrate obtain a smaller percent yield of product than a student using 0.650 g? Explain your answer. During the experiment when all of the limiting reactant has reacted, how many moles of the other reactant remain unreacted? Show your calculations & explain your answer clearly. The liquid that goes through the filter paper into the filter flask is called the filtrate. What exactly is in your filtrate? List all the substances that you can think of that are in the filtrate.Explanation / Answer
1. We will have to take minimum amount of water, since the resultant complex (Tris(ethylenediamine)Nickel(II) chloride) is sparingly soluble in water. If we add more amount of water more amount of complex will be soluble and it will pass through filter paper, then yield will be less.
2. No. Percentage yield won't differ if the amount of limiting reagent is varied within the limit of excess reagent. Since, the limiting reagent reacts completely to the excess reagent in both the cases.
3. This question requires amount of limiting reagent and excess reagent in grams/ml.
First, convert volume of ethylene diamine in to grams by using the following formula:
Mass = Density x Volume
Then, calculate number of moles for each reagent and substract it.
Number of moles = Weight in grams / Molar mass in g mol-1
4.
Ethylene diamine (excess)
Water
Unreacted NiCl2 (if any)
Solvents which you have used to wash the precipitate
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