Hi, I am providing all of the information as it is probably needed to answer the

Question

Hi, I am providing all of the information as it is probably needed to answer the last couple of questions. I need help answering the last three boxes.

1. Calculate the heat released into the solution for the 3 reactions, according to Reaction= Ccal*Delta T+ m contents * Cp contents * Delta T.

2. Find the molar heat of reaction for each experiment in units of Kilo-Joules / (mole of Mg) by dividing the heat of reaction by the moles of Mg used.

3. Calculate and record the average molar heat of reaction from the three results.

Thank you for your help.

The Effect of Substrate Concentration on Catalase Activity

A. Mass of the empty calorimeter (g):

18.600g

B. Initial temperature of the calorimeter (°C):

21.5C

C. Maximum temperature in the calorimeter from the reaction (°C):

34.5C

D. Calculate delta T by subtracting (b) from (c) (°C) delta T = Tmaximum – Tinitial:

34.5-21.5 = 13C

E. Mass of the calorimeter and its contents after the reaction (g):     

68.738g

F. Calculate the mass of the contents of the calorimeter (g) by subtracting (a) from (e)         

68.738-18.600=50.138g

G. Calculate the moles of Mg reacted (MW = 24.305 g/mole)

50.138/24.305=2.0628 moles

The Effect of Substrate Concentration on Catalase Activity 2

A. Mass of the empty calorimeter (g):

18.600g

B. Initial temperature of the calorimeter (°C):

21.5C

C. Maximum temperature in the calorimeter from the reaction (°C):

43.2C

D. Calculate delta T by subtracting (b) from (c) (°C) delta T = Tmaximum – Tinitial:

43.2-21.5= 21.7C

E. Mass of the calorimeter and its contents after the reaction (g):     

68.829g

F. Calculate the mass of the contents of the calorimeter (g) by subtracting (a) from (e)         

68.829-18.600=50.229g

G. Calculate the moles of Mg reacted (MW = 24.305 g/mole)

50.229/24.305=2.066moles

The Effect of Substrate Concentration on Catalase Activity 3

A. Mass of the empty calorimeter (g):

18.600g

B. Initial temperature of the calorimeter (°C):

21.5C

C. Maximum temperature in the calorimeter from the reaction (°C):

51.8C

D. Calculate delta T by subtracting (b) from (c) (°C) delta T = Tmaximum – Tinitial:

51.8-21.5= 30.3C

E. Mass of the calorimeter and its contents after the reaction (g):     

68.921g

F. Calculate the mass of the contents of the calorimeter (g) by subtracting (a) from (e)         

68.921-18.600=50.321g

G. Calculate the moles of Mg reacted (MW = 24.305 g/mole)

50.321/24.305=2.07moles

Calculate the heat released into the solution for the 3 reactions, according to: Reaction= Ccal*Delta T+ m contents * Cp contents * Delta T

Trial 1

Trial 2

Trial 3

Find the molar heat of reaction for each experiment in units of Kilo-Joules / (mole of Mg) by dividing the heat of reaction by the moles of Mg used.

Trial 1

Trial 2

Trial 3

Calculate and record the average molar heat of reaction from the three results.

Average

The Effect of Substrate Concentration on Catalase Activity

A. Mass of the empty calorimeter (g):

18.600g

B. Initial temperature of the calorimeter (°C):

21.5C

C. Maximum temperature in the calorimeter from the reaction (°C):

34.5C

D. Calculate delta T by subtracting (b) from (c) (°C) delta T = Tmaximum – Tinitial:

34.5-21.5 = 13C

E. Mass of the calorimeter and its contents after the reaction (g):     

68.738g

F. Calculate the mass of the contents of the calorimeter (g) by subtracting (a) from (e)         

68.738-18.600=50.138g

G. Calculate the moles of Mg reacted (MW = 24.305 g/mole)

50.138/24.305=2.0628 moles

Explanation / Answer

Trial 1

heat caoacity of Calorimeter= 62.558 J/deg.c

Specific heat of Zinc =0.39 Kj/Kg.K =0.39 J/gm.K

Heat added for raising the temperature of calorimeter= 62.558*13.2+ 50.138*13.2*0.39 =1083.876 Joules=1.083876 KJ

Heat of reaction = 1.083876/2.0628=0.525 Kj/Mol

Trial 2

Heat released =21.7*62.558+21.7*50.229*0.39 =1782.597 Joules =1.782597 KJ

Heat released per mole = 1.782597/2.066=0.862 Kj/mol

Trial3

Heat releasted =62.558*30.3+ 30.3*0.39*50.321=2490.151 Joules= 2.490151 Kj

Hear released per mole of Mg= 2.490151/2.07=1.202 Kj/Mole

Average= (0.525+0.862+1.202)/3= 0.863 Kj/mol

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