The following table shows the magnetic moment for a number of complexes. The uni

Question

The following table shows the magnetic moment for a number of complexes. The unit of magnetic moment is the Bohr magneton.

a) Indicate the number of unpaired electrons in each complex.

b) Based on the number of unpaired electrons and the number of d electrons determine if any of the complexes are low spin or high spin. For octahedral complexes only d4, d5, d6 and d7 metals can be either low or high spin.

Explanation / Answer

dipole moment = sqrt(n(n+2))
a)
for 1st complex:
1.82^2 = n(n+2)
3.3124 = n^2 + 2n
n^2 + 2n - 3.3124 = 0
solving above quadratic equation, we get one positive value of n
n=1
Answer 1 unpaired electron

for 2nd complex:
3.82^2 = n(n+2)
14.5924 = n^2 + 2n
n^2 + 2n - 14.5924= 0
solving above quadratic equation, we get one positive value of n
n=3
Answer 3 unpaired electron

for 3rd complex:
1.85^2 = n(n+2)
3.4225 = n^2 + 2n
n^2 + 2n - 3.4225 = 0
solving above quadratic equation, we get one positive value of n
n=1
Answer 1 unpaired electron

for 4th complex:
4.95^2 = n(n+2)
14.5 = n^2 + 2n
n^2 + 2n - 24.5= 0
solving above quadratic equation, we get one positive value of n
n=4
Answer 4 unpaired electron

b)
Only 4th complex has d5
so only 4th one is high spin

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.