Don\'t really understand this please help. Thanks!!(: For the reaction H2(g) + I

Question

Don't really understand this please help. Thanks!!(: For the reaction H2(g) + I2(g) doubleheadarrow 2HI(g), K2=0.170 at 500, K. What concerntration of I2(g) will be in equilibrium with H2=0.0150M? Consider the reaction PCI5(g) doubleheadarrow PCI3(g) + CI2(g) At 250, ^a C2 it is found that at equilibrium, the initial PCI5 is 45.0% decomposed. If 0.110 mol of PCI9(g) is introduced into a 1.00L container at 250.^a C, what will be the equilibrium concerntrations of PCI5,PCI3.and CI2? What is the value of K4?

Explanation / Answer

5.

H2(g) + I2(g) <-----------> 2HI(g)

Kc = [HI]^2 / [H2] [I2]

0.170 = ( 0.015)^2 / ( 0.04 * [I2] )

[I2] = ( 0.015)^2 / ( 0.04 * 0.17)

[I2] = 0.0331 M

6.

PCl5 gets dissociated by 45% of initial amount

PCl5(g)     ---------->    PCl3(g)   +         Cl2(g)

0.11                                0                        0          ( initial moles)

- ( 0.45 * 0.11)         + ( 0.45*0.11)        + ( 0.45 * 0.11)    ( Dissociated moles)

0.0605                         0.0495                0.0495               ( Final moles)

Equilibrium concentrations are

[PCl5] = 0.0605 mol / 1 L = 0.0605 mol/L

[PCl3] = 0.0495 mol/L

[Cl2] = 0.0495 mol/L

Kc = [PCl3] [Cl2] / [PCl5]

Kc = (0.0495 * 0.0495) / 0.0605

Kc = 0.0405 mol/L

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