In step 5, of the experiment, a student accidentally added 6M CuCl 2 instead of

ID: 896443 • Letter: I

Question

In step 5, of the experiment, a student accidentally added 6M CuCl2 instead of HCl. How will this affect the result of the experiment?

will cause mass of Cu recovered to be greater. This is because CuCl2 solution will not react with Zn metal resulting in a mixture of Cu and Zn in the recovered product.

there will be no effect in the final result

will cause the amount of Cu recovered to be greater than if HCl was used. This is because Cu is more active than Zn causing more Cu metal to form.

will cause the amount of Cu recovered to be greater than if HCl was used. This is because Cu is less active than Zn causing more Cu metal to form.

will cause mass of Cu recovered to be greater. This is because CuCl2 solution will not react with Zn metal resulting in a mixture of Cu and Zn in the recovered product.

there will be no effect in the final result

will cause the amount of Cu recovered to be greater than if HCl was used. This is because Cu is more active than Zn causing more Cu metal to form.

will cause the amount of Cu recovered to be greater than if HCl was used. This is because Cu is less active than Zn causing more Cu metal to form.

Explanation / Answer

D. will cause the amount of Cu recovered to be greater than if HCl was used. This is because Cu is less active than Zn causing more Cu metal to form.

this is because Cu^+2 is havig more reduction potetial than H+ AND Zn^+2 .so hence Cu^+2 undergo reduction to form Cu solid

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In step 5, of the experiment, a student accidentally added 6M CuCl 2 instead of

In step 5, of the experiment, a student accidentally added 6M CuCl2 instead of H

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In step 5, of the experiment, a student accidentally added 6M CuCl 2 instead of

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