Question is: Hydrogen has two naturally occurring isotopes H (atomic mass 1) and

Question

Question is: Hydrogen has two naturally occurring isotopes H (atomic mass 1) and D (atomic mass 2). A mixture containig an equal number of moles of H2 and D2 is allowed to effuse down a capillary. What percent of the molecules effusing first will be D2?

My answer: Since the rate of effusion of a gas has the same form as Graham's Law of Diffusion, and given D2 has a molar mass of aproximately twice that of H2, then the lighter H2 molecules will be first. Thus, 0% of the D2 molecules will effuse first.

Explanation / Answer

Solution :-

Rate of the diffusion of the gas is calculated as

rate H2/rate D2 = molar mass of D2/molar mass of H2

                          = 4.04/2.02

                         = 2

So when 1 molecule of the D2 effuse at that time 2 molecules of H2 will diffuse

so the percent of the D2 = (1/(1+2)*100%

                                       = 33.33 %

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