(Please show method and all work in latex for readability. Test is tomorrow) 4.

Question

(Please show method and all work in latex for readability. Test is tomorrow)

4. The catalytic homogeneous reaction:

2A 2D + E       takes place in two steps

1) A + 2B C + 2D

2) A + C E + 2B

and step 1 has a forward activation energy of 20 kJ/mol and a reverse activation energy of 40 kJ/mol while step 2 has a forward activation energy of 40 kJ/mol and an enthalpy of – 40 kJ/mol.

a) ( 4 pts) What is the value of the enthalpy of the overall reaction? ___________

b) (3 pts) Which step 1 or 2 is the rate determining step ? __________

c) ( 4 pts) Which species is the catalyst ________ and which is the intermediate ________ .

d) (5 pts ) Sketch the potential energy profile and put in values of the forward activation

energies and the total enthalpy on the sketch.

e) ( 3 points) A catalyst lowers the _________________ of the rate determining step

Explanation / Answer

a) The value of the enthalpy of the overall reaction is = 20 - 40 -40 = -60 KJ/mole

b) Step 1 is the rate determining step

c) C is the catalyst and C is the intermediate

e) A catalyst lowers the energy of the rate determining step

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