The attractive forces between molecules of a substance and their container is ca

Question

The attractive forces between molecules of a substance and their container is called The temperature where all three phases of a substance are is equilibrium is called the point. Raoult's law involves a relationship between the mole fraction and the of the gas in a solution. The abbreviation for the concentration unit of the ratio of solute mass to solution mass times one billion is When the temperature increases most gases become soluble in solution. Methanol, CH_3OH, has specific heat of 0.328 cal/g degree C for its vapor and its heat of vaporization is 35.21 kJ/mole at its boiling point of 64.60 degree C. Calculate the specific heat in J/g degree C of liquid methanol if 122.1 kJ of heat is required to convert 100.0 g of liquid methanol at 32.60 degree C to vapor at 95.60 degree C. At wts: C = 12.00 g/mol, H=1.008 g/mol and O = 16.00 g/mol. 1cal = 4.1840 J.

Explanation / Answer

1) is called .....adhesive forces

   is called .....Triple point

   and between ...molality

abbrevation is ppb ( parts per billion)

Gas becomes less soluble

2) we know that

Q1 = m X specific heat X DeltaT

Q = mass X specific heat X (T2-T1)

Q2 = m(heat of vaporization)

Two steps -

liquid to boiling point

Conversion of liquid to vapours

Q1 = 100 X0.328 X (64.6 - 32.6) = 1049.6 J ( for boiling)

MAss = 100 g

So moles = mass / molecular weight = 100 / 32 = 3.125 moles

Q2 = 3.125 X 35.21 Kj / mole = 110.031 kJ = 110031 J

On adding the two heat

Q1+Q2 = 1049.6 + 110031 = 111080 Joules

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