How will the following situations affect your final calculation of molarity of H

Question

How will the following situations affect your final calculation of molarity of HC_2H_2O_2? You wash the sides of the flask with deionized water to remove any vinegar or NaOH solution adhering to the side of the flask. You add 20mL of water to the vinegar in the flask (assume no drops of vinegar adhere to the side of the flask) The tip of the buret is not filled when you start a titration but is filled when you finish the titration. The molarity of the standard NaOH solution is miscalculated and the true value is higher than the concentration given As you are refilling your buret, some of the NaOH spills over the side and runs down the buret into the flask you intend to titrate.

Explanation / Answer

from this we under stnad you are titrating acetic acid with NaOH

a)

the molarity of the compound present in the flask will decrease because you are diluting the solution present in the flask

b)

mlarity of the venigar will decrease

becuse you are diluting

c)

hogher molarty value you will get

if you didnot fill the burett tip means you are feeling NaOH reading more but actually it is less there in burette

that means you felt more concentration of AcOH than what is there

d)

Molarity of venigar you will get the low value.

e)

concentration will decrease.

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