The Born-Haber cycle is a series of steps that represent the formation of an ion

Q: The Born-Haber cycle is a series of steps that represent the formation of an ion

K(S) should convert to K(g) which we called sublimation DHsub of K dissociation of F2 molecule to F atom which we called 1/2BE of F2 the F atom should convert to F- which we called EA of F so from the above interpretation we can say the second option is correct

ID: 895266 • Letter: T

Question

The Born-Haber cycle is a series of steps that represent the formation of an ionic compound from a metal and a nonmetal. For example, the steps in a Born-Haber cycle for the formation of NaCl(s) consist of sublimation of the metal Na atom (Hsubl-Na) to form a gaseous Na atom, bond dissociation of the chlorine molecule (BECl2) to form a gaseous Cl atom, ionization energy of the sodium atom (IENa) to form a gaseous Na+ ion, electron affinity of the chlorine atom (EACl) to form a gaseous Cl- ion, and the lattice energy of NaCl (LENaCl) involving the coalescing of the gaseous Na+ and Cl- ions to form a solid NaCl formula unit.

With the above summary in mind, which particular steps of the Born-Haber cycle would be represented in the following reaction?

K(s) + ½F2(g) K(g) + F(g)

Hsubl-K and EAF

Explanation / Answer

K(S) should convert to K(g) which we called sublimation DHsub of K

dissociation of F2 molecule to F atom which we called 1/2BE of F2

the F atom should convert to F- which we called EA of F

so from the above interpretation we can say the second option is correct

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The Born-Haber cycle is a series of steps that represent the formation of an ion

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The Born-Haber cycle is a series of steps that represent the formation of an ion

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