If you have 1e- and 2 e- in the two equations, your least common multiple is 2,

Question

If you have 1e- and 2 e- in the two equations, your least common multiple is 2, so you would multiply the first equation by two and second by 1.

So, n = 2 in that case.



DelG = -n*F*E. The only part remaining is E. To find the total Emf of the cell, you would first determine which E is larger between the reactions. This one has the larger Standard Reduction Potential, i.e. it will be reduced (meaning electrons in the reactants side).

Using this information and by re-organizing the equations you should get a delG value.

*Note that because E is an "intensive property" changing the number of electrons in one equation does not change that half reaction's E value, it will only be negated if you flip the reaction such that electrons are now on the opposite side.

Explanation / Answer

The one with lower Eo value acts as anode and the one with higher Eo value will acts as anode.

Eo cell = Eo cathoce - Eo anode
              = 0.8 - (-0.13)
               = 0.93 V

delta Go = -n*F*Eo
                  = -2*96500*0.93
                  = -179490 J
                  = -179.49 KJ

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