Data 1A: (Please fill out this table and submit with the lab report. Recopy if m
ID: 894548 • Letter: D
Question
Data 1A: (Please fill out this table and submit with the lab report. Recopy if messy)
For each piece of glassware, calculate the mass of the water added, then use the density of water (0.998 g/mL) to find the calculated volume of the water. Record your three volume calculations below. Be sure to that all measurement include the correct number of significant figures and appropriate units.
100 mL beaker
10 mL grad. cyl.
100/50 mL grad. cyl.
Dry Mass
59.548g
38.640g
87.003g
Dry Mass of container
+ H2O
72.199g
48.548g
95.905g
Mass of H2O
(subtract the masses)
12.651g
9.908g
8.902g
CalculatedVolume
(from mass of H2O)
12.676mL
9.926mL
8.920mL
Sample Calculations: (Show a sample of each type of calculation you did)
Mass of H2O = (Dry mass of container + H2O) – (Dry mass)
72.199g – 59.548g = 12.7g
Volume = mass of H2O / Density of Water
12.651g/ 0.998g/mL =12.7mL
Data 1B: (Please fill out this table and submit with the lab report. Recopy if messy)
Metal A
Metal B
Metal C
Metal D
Metal E
Mass of metal(g)
17.077mL
5.417g
22.704g
15.174g
13.655g
Initial Volume
of Water
10.1mL
10.3mL
10.5mL
9.9mL
11.2mL
Volume of water
+ metal (mL)
12.2mL
12.1mL
12.3mL
11.8mL
12.3mL
Volume of metal (mL)
(subract volumes)
2.2mL
1.8mL
1.8mL
1.9mL
2.1mL
Density of metal
(g/mL)
8.9g/mL
3.0g/mL
13g/mL
8.0g/mL
6.5g/mL
Identity of metal
Cu
Al
Pb
Fe
Zn
Sample Calculations: (Show a sample of each type of calculation you did)
Calculations
1. Volume of Metal = (volume of water + metal) – (initial volume of water)
12.2mL – 10.1mL = 2.1mL
2. Density of Metal = mass of metal / volume of metal
17.077g / 2.1Ml =8.1g/mL
Need help with the question below
Determination of percent error (for glassware and metal densities)
Typed discussion of measured results vs literature results and description of possible sources of error. Note that “human error” is not an acceptable answer. Please be specific.
100 mL beaker
10 mL grad. cyl.
100/50 mL grad. cyl.
Dry Mass
59.548g
38.640g
87.003g
Dry Mass of container
+ H2O
72.199g
48.548g
95.905g
Mass of H2O
(subtract the masses)
12.651g
9.908g
8.902g
CalculatedVolume
(from mass of H2O)
12.676mL
9.926mL
8.920mL
Explanation / Answer
Calculated Density of Metal A = 17.077 / 2.1 = 8.1 g/mL
Observed density of metal A = 8.9 g/mL
% error in density of metal A = 8.9 - 8.1 / 8.9 * 100 = 8.98%
% error in density of metal B = (3.01 - 3 / 3) * 100 = 0.3%
% error in density of metal C = ( 13 - 12.61 / 13 ) * 100 = 2.97%
& error in density of metal D = ( 8 - 7.99 / 8 ) * 100 = 0.125%
% error in density of metal E = ( 6.502 - 6.5 / 6.5 ) * 100 = 0.03 %
So,
Metal A - Measured Density = 8.9 g/mL and Observed density = 8.1 g/mL
Metal B - Measured Density = 3 g/mL and Observed density = 3.01 g/mL
Metal C - Measured density = 12.61 g/mL and Observed density = 13 g/mL
Metal D - Measured Density = 7.99 g/mL and Observed density = 8.00 g/mL
Metal E - Measured density = 6.502 g/mL and Observed density = 6.5 g/mL
Sources of error
Error in weight balance is possible if it is not zeroed
Incorrect measurement of volume due to defects in glassware
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.