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Bringing It Together: Question 13.2 A reaction has the stoichiometry: 3A + B C +

ID: 893185 • Letter: B

Question

Bringing It Together: Question 13.2 A reaction has the stoichiometry: 3A + B C + D. The following data were obtained for the initial rate of formation of C at various concentrations of A and B.

Initial Concentration

[A]

[B]

Initial Rate of Formation of C

(mol L-1 s-1)

0.10

0.10

0.040

0.20

0.20

0.16

0.20

0.10

0.16

(a) What is the rate law for the reaction? Rate = k [A]0[B]2 Rate = k [A]2[B]0 Rate = k [A]1[B]1 Rate = k[A]2[B]2 None of these.

(b) What is the rate constant for the reaction? L mol-1 s-1 the tolerance is +/-1 in the 2nd significant digit

(c) What is the rate at which C is formed if [A] = 0.44 M and [B] = 0.75 M? mol L-1 s-1 the tolerance is +/-1 in the 2nd significant digit

Initial Concentration

[A]

[B]

Initial Rate of Formation of C

(mol L-1 s-1)

0.10

0.10

0.040

0.20

0.20

0.16

0.20

0.10

0.16

Explanation / Answer

from Trial 1 and Trial 3

When Concentration of A is doubled without a change in concentration of B, the rate has increased by 4 times. This suggests the rate to be proportional to [A]2 and no dependence of rate on B. This is further confimred that

from Trail 2 , when A is doubled and B is also doubled, there is a four times increase in rate expression

Hence Rate expression reads Rate= K [A]2

Where K is the rate constant

From trial 1

0.040 =K (0.1)2

K =0.040/(0.1)2 = 4 Lmol-1s-1

Rate of formation of C= 4 * [0.44]2 = 0.1936 Mol/L.sec

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