7.What are the products of the acid–base reaction of sodium carbonate with aceti

Question

7.What are the products of the acid–base reaction of sodium carbonate with acetic acid?

A)

CO(g) + H2O(l) + 2 NaCH3COO(aq)

B)

5 CO2(g) + 2 H2O(l) + 2 NaOH(aq)

C)

H2CO3(aq) + H2O(l) + 2 NaOH(aq)

D)

CO2(g) + H2O(l) + 2 NaCH3COO(aq)

8.Which salt forms a basic solution when dissolved in water?

A) KCl B) NaCO3 C) LiNO3 D) NaCl

9.Which salt forms a solution with a pH < 7 when dissolved in water?

A) NaCl B) CH3COONa C) NH4Cl D) LiNO3

11.

In the acid-base titration experiment, volume of base is measured as

A) Final Read + Initial Read B) Initial Read - Final Read C) Final Read - Initial Read D) 10 ml

In the acid-base titration experiment, basic solution is in a(n)

A) beaker B) buret C) Erlenmeyer flask D) cylinder

Explanation / Answer

7) Sodium carbonate reacts with acetic acid to form Sodium acetate CH3COONa, Carbon dioxide CO2 and water H2O.

So the answer is

D) CO2(g) + H2O(l) + 2 NaCH3COO(aq)

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Theory for answering questions 8 and 9:

The solution of the salt of a Strong acid and a Strong base is Neutral    pH=7

The solution of the salt of a Strong acid and a Weak base is Acidic        pH is less than 7

The solution of the salt of a Weak acid and a Strong base is Basic          pH is greater than 7

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8) Na2CO3 is the salt of the Strong base NaOH and weak acid H2CO3 (Carbonic acid). Hence its solution is basic

So the Answer is   B) Na2CO3 ( not NaCO3)

All the other salts are salts of strong acid and strong base. Hence their solutions are neutral

9) C) NH4Cl

NH4Cl is the salt of the strong acid HCl and weak base NH4OH . Hence its solution will be acidic and pH < 7

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11)   In the acid-base titration experiment, a known volume of the base is pipetted out into a conical flask(Erlenmeyer flask ) and the acid is taken in the burette

Hence the answer is   D) 10 ml     (or any other known volume)

12) In the acid-base titration experiment, basic solution is in a(n)

C) Erlenmeyer flask  

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