The equilibrium constant, K , of a reaction at a particular temperature is deter

Question

The equilibrium constant, K, of a reaction at a particular temperature is determined by the concentrations or pressures of the reactants and products at equilibrium.

For a gaseous reaction with the general form

aA+bBcC+dD

the Kc and Kp expressions are given by

Kc=[C]c[D]d[A]a[B]b

Kp=(PC)c(PD)d(PA)a(PB)b

The subscript c or p indicates whether K is expressed in terms of concentrations or pressures. Equilibrium-constant expressions do not include a term for any pure solids or liquids that may be involved since their composition does not change throughout the reaction. The standard state of a pure substance is the pure substance itself, and although the quantity may change the sample remain pure. The concentration is effectively equal to 1, and will not impact the magnitude of K.

Phosgene (carbonyl chloride), COCl2, is an extremely toxic gas that is used in manufacturing certain dyes and plastics. Phosgene can be produced by reacting carbon monoxide and chlorine gas at high temperatures:

CO(g)+Cl2(g)COCl2(g)

Carbon monoxide and chlorine gas are allowed to react in a sealed vessel at 479 C . At equilibrium, the concentrations were measured and the following results obtained:

What is the equilibrium constant, Kp, of this reaction?

Express your answer numerically.

Deriving concentrations from data

In Part A, you were given the equilibrium pressures, which could be plugged directly into the formula for K. In Part B however, you will be given initial concentrations and only one equilibrium concentration. You must use this data to find all three equilibrium concentrations before you can apply the formula for K.

Part B

The following reaction was performed in a sealed vessel at 758 C :

H2(g)+I2(g)2HI(g)

Initially, only H2 and I2 were present at concentrations of [H2]=3.10M and [I2]=3.00M. The equilibrium concentration of I2 is 0.0600 M . What is the equilibrium constant, Kc, for the reaction at this temperature?

Express your answer numerically.

Explanation / Answer

using the given formula,

Kp = (0.16)/(1.3*0.77) = 0.16 atm-1

Part B

Initial :

[H2] = 3.1

[I2] = 3

Final :

[I2] = 0.06

Amount of [I2] consumed = x = 3 - 0.06 = 2.94

Therfore,

[H2] final = 3.1 - 2.94 = 0.16

and amount of [HI] formed = 2x = 5.88

Using the given formula for Kc

Kc = (5.88)2 / (0.16*0.06)

= 3601.5

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