Under laboratory conditions, a photosynthetic organism might convert 31% of the

Question

Under laboratory conditions, a photosynthetic organism might convert 31% of the light energy striking it to chemical bond energy of organic molecules. In reality, however, photosynthetic efficiency is far lower, closer to 5% or less. Considering a plant growing in a natural environment, suggest the reasons for this discrepancy. Select the four correct answers. Many leaves may be shaded by in the above them Some of the energy is for a plant growth. There might be not oxygen in the air. There is no at night

Explanation / Answer

Photosynthesis is a biochemical process in which light energy is converted in to chemical enegy .The total amount of light which comes from sun never absorbed 100%, only 11% of total light is absorbed remaining is reflected by them. Energies are used in different puprposes such as in Respiration,Photosynthesis and Reflection etc. only 3-6% pecent of absorbed light is use for biomass i.e., Photosynthesis. Energy is also released in the form of heat. Because the light 3-6 % is enough for photosynthesis in any condition. Excess energy may damage photosynthetic apparatus .

According to the statement given in part A-- when we talk about the plants growing in the natural condithions then we can see an example of that plat which are shrubs and present under the canopy of large trees which are completely shaded. Here we can see that there is no problem in photosynthessis of that shrub because that <1% energy is enough for that.

Reason why only 3-6% light is used from absorbed 11% light for photosynthesis :-

Not all the light is absorbed by plants ,only the light in PAR region is absorbed that is from 400nm - 700nm. PAR means photosynthetically active region .

So in laboratory 31% of light is used for chemical bond energy is the energy for biomass production ,in other words it is photosynthesis.

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