During lab, students mixed two solutions of soluble ions in a ceramic well to de

Question

During lab, students mixed two solutions of soluble ions in a ceramic well to determine if a precipitate forms.

Based on extrapolation of your lab results, write the dissolution reaction for the ionic solids below. (Use the lowest possible coefficients. Include states-of-matter under the given conditions in your answer.)

(a)    Cu(ClO4)2

(b)    Li2CO3

The two solutions, when mixed, will have two cations and two anions.

(c) Based on your lab results, enter the cation and anion for which a precipitate will form. (Separate substances in a list with a comma.)

(d) Write the net precipitation reaction that occurs. (Use the lowest possible coefficients. Include states-of-matter under the given conditions in your answer.)

Explanation / Answer

It is not mentioned in the description but let us consider the solution was aqueous.

Four ions formed are, Cu2+, Li+, ClO4-, CO32-

It is known from the solubility data that LiClO4 is soluble in water but copper carbonate is not soluble in water and will precipitate out from the aqueous solution.

Cu(ClO4)2 (aq) +Li2CO3(aq) = CuCO3 (solid, precipitated) + 2LiClO4 (soluble, aqueous)

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