Cu(s) --> [Cu(H 2 O) 6 ] 2+ (aq) --> Cu(OH) 2 (s) --> CuO(s) --> [Cu(H 2 O) 6 ]

Question

Cu(s) --> [Cu(H2O)6]2+(aq) --> Cu(OH)2(s) --> CuO(s) --> [Cu(H2O)6]2+(aq) --> Cu(s)

(a)what test will you perform to determine when you have added sufficient NaOH solution to the reaction mixture in Reaction II [Cu(H2O)6] 2+ (aq) + 2 OH- (aq) Cu(OH)2 (s) + 6 H2O (l) , H3O+ (aq) + OH- (aq) 2 H2O (l)

(b)Briefly explain what you would observe if you used the test described in (a) on a solution that needed more NaOH solution

(c)how will you determine whether or not you have added sufficient Mg in Reaction V:[Cu(H2O)6] 2+ (aq) + Mg (s) Cu (s) + Mg 2+ (aq) + 6 H2O (l)? Briefly explain.

(d) what test will you perform to determine whether or not the Mg added in reactionV:[Cu(H2O)6] 2+ (aq) + Mg (s) Cu (s) + Mg 2+ (aq) + 6 H2O (l) has completely reacted?

Explanation / Answer

a)

precipitation test, (if you see solids, you have Copper as Cu(OH)2

Also, if there is no more Cupper in solution, you will not expect the typical blue color of the solution

b)

IF you needed more NaOH (this menas there is more Copper in solution) you will see the blue solution

c)

Take out the precipitate (Copper as solid) then add again MG to expect more precipitation, if there is no more precipitate, then you are done

d)

You will expect a color change from the complex Cu(H2O)6]+2

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