Stoichiometry Problems for Reaction in Aqueous Solutions 1. How many grams of Ca

Question

Stoichiometry Problems for Reaction in Aqueous Solutions

1.How many grams of Ca(OH)2 are needed to neutralize 25.0 mL of 0.250 M HNO3?

2.How many milligrams of sodium sulfide are needed to completely react with 50.00 mL of a 0.100 M aqueous solution of cadmium nitrate, to form a precipitate of CdS(s)?

3.How many grams of NaOH are needed to neutralize 25.0 mL of 0.50 M H2SO4 solution? (b) How many liters of 0.400 M HCl(aq) are needed to react completely with 0.200 mol of Pb(NO3)2(aq), forming a precipitate of PbCl2(s)?

4. One commercial method used to peel potatoes is to soak them in a NaOH solution for a short time and then remove the potatoes and spray off the peel. The NaOH concentration is normally 3 to 6 M, and the solution must be analyzed periodically. In one such analysis, 55.7 mL of 0.500 M H2SO4 is required to neutralize 25.0 mL of

Explanation / Answer

1. 25.0 mL of 0.250 M HNO3 moles = 0.25*0.025L = 0.00625 mol

Ca(OH)2 + 2HNO3 ----------->   Ca(NO3)2 + 2H2O

It means 74g/mol (1 mol)Ca(OH)2 required to nutralise HNO3 is 2 mol(2*63g/mol)

then 0.00625 mol HNO3 require Ca(OH)2 moles = 0.00625*1/2 = 0.003125 mol

grams of Ca(OH)2 are needed to neutralize 25.0 mL of 0.250 M HNO3 = 0.003125 mol*74g/mol = 0.23125g

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