1. The following reaction is done at 298.15 K and 1 atm: N2H4 (l) + CH3OH (l) CH

Question

1. The following reaction is done at 298.15 K and 1 atm:

N2H4 (l) + CH3OH (l) CH2O (g) + N2(g) + 3H2 (g)        Horxn  = -37 kJ

How much work is done? The answer should be -12.5.

2. A reaction is carried out at 25 C, 1 atm, 1 mol, and 1200 L. The Horxn  = -100 kJ. Assume only pressure-volume work is done and temperature remains constant. Calculate Erxn.

3. 100.0 g of dry ice is sealed in a 5.00 L container previously containing only0.2500 moles of pure oxygen at a temperature of 50.0oC and pressure of 1.33 atm. What is the Total pressure of gas in the container if all of the dry ice sublimes?

and the temperature is held constant at 50.0oC.

Explanation / Answer

1.  N2H4 (l) + CH3OH (l) CH2O (g) + N2(g) + 3H2 (g)

delta n=np-nr= 5-0= 5 ( as reactant in liquid phase)

work done=- deltan.RT

w=-5*8.314*298.15= -12432.8 J or -12.5 KJ

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