Need coupling constant (J value, to one decimal place, in Hz) for all mulitplets
ID: 889759 • Letter: N
Question
Need coupling constant (J value, to one decimal place, in Hz) for all mulitplets possible.
' ppm Hz Intensity In MN Q on an M NV s o o o n n m 0 0 0 0 NNN 0 0 0 0 0 In In O O O o o o o o 0 FT + 0 0 0 0 0 0 0 0 0 0 0 0 0 0 T T T HHHHHH no o o o o o o o o o o o o o 1 4.05 1619.6 12433 2 4:03 16127 2475.9 3 4.02 16058 1279.2 4 199 794.2 76.6 5 1.8 7910 9340.1 6 167 666.1 163.4 7 1.65 659.4 335.0 8 1.63 652.7 440.6 In MN 0 0 0 + T 0 0 NNN 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 O o o o o o g Oooo 9 162 646.2 259.6 10 1.61 645.6 1959 11 1.60 639.6 1010 12 1.60 639.0 164.8 13 149 593.9 7474 14 147 587.0 2190.2 15 1,45 580.1 1868.0 16 143 573.3 558.3 17 0.88 352.3 53.6 18 0.88 351.8 86.6 19 0.88 351.3 136.9 20 0.88 350.8 122.4 430 425 420 415 4.10 4.05 4.00 395 3,90 21 0.87 348.8 10058.6 f1 (ppm 2 0.87 3466 119.5 0.95 0.0 0.85 fil (ppm) 23 0.87 346.2 113.5 24 0.86 345.7 53.4 NL MN Oo 0 0 0 0 0 0 0 HHHHHHH ON IN HHHH SSS V ||| 25 0.86 3452 84.2 26 0.86 3447 108.9 | 27 0.86 344.2 52.2 28 0.86 42.2 9672.8 29 0.85 339.9 4.0 30 0.85 339.5 120.7 1.75 1.70 1.65 1.60 1.55 150 1.45 1.40 13 1211 109 f1 (ppm)Explanation / Answer
J= (ppm) * Larmor (MHz)
4.05, 4.03, 4.02
Generally Larmor (MHz) = 270 MHz)
[if for your spectra it is different then put that values.]
(ppm) = 4.05 -4.03 = 0.02 ppm
J= 0.02(ppm) * 270 (MHz) = 5.4 Hz
(ppm) = 4.03 -4.02 = 0.0 ppm
J= 0.01(ppm) * 270 (MHz) = 2.7 Hz
1.49, 1.47, 1.45, 1.43:
(ppm) = 1.49 -1.47= 0.02 ppm
J= 0.02(ppm) * 270 (MHz) = 5.4 Hz
(ppm) = 1.47 -1.45= 0.02 ppm
J= 0.02(ppm) * 270 (MHz) = 5.4 Hz
(ppm) = 1.47 -1.45= 0.02 ppm
J= 0.02(ppm) * 270 (MHz) = 5.4 Hz
(ppm) = 1.45 -1.43= 0.02 ppm
J= 0.02(ppm) * 270 (MHz) = 5.4 Hz
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