when 0.89g of an unknown no electrolyte is dissolved in 50.0g of benzene the fre
ID: 888738 • Letter: W
Question
when 0.89g of an unknown no electrolyte is dissolved in 50.0g of benzene the freezing point decreased by 0.48 Celsius. if the KP of the solvent is 5.12 K/m calculate the molar mass of the unknown solute when 0.89g of an unknown no electrolyte is dissolved in 50.0g of benzene the freezing point decreased by 0.48 Celsius. if the KP of the solvent is 5.12 K/m calculate the molar mass of the unknown solute when 0.89g of an unknown no electrolyte is dissolved in 50.0g of benzene the freezing point decreased by 0.48 Celsius. if the KP of the solvent is 5.12 K/m calculate the molar mass of the unknown soluteExplanation / Answer
delta Tf= Kf * m
here mis molaity
m = mass / (molarr mass * mass of solvent in Kg)
m = 0.89 / (M*0.05)
= 17.8 /M
putting in:
delta Tf= Kf * m
0.48 = 5.12*(17.8/M)
M = 5.12*17.8 / 0.48
= 189.9 gm
Answer: 189.9 gm
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