1. Is the equivalence point of a weak acid-strong base titration acidic, neutral
ID: 888107 • Letter: 1
Question
1. Is the equivalence point of a weak acid-strong base titration acidic, neutral, or basic?
2. How is pKa determined from a weak acid-strong base titration?
3. A 0.6385 g sample of KHP is titrated to endpoint with 33.46 mL of NaOH. What is the NaOH concentration?
4. An unknown sample with a mass of 1.0 g requires 11.5 mL of titrant. What mass of unknown should be used for an analytical titration, with an approximate equivalent volume of 35 mL?
5. How is an endpoint found from a 2nd Derivate Potentiometric Titration plot?
pleeeease help me ASAP
Explanation / Answer
1)
the equivalence point of a weak acid strong base titration will be basic
2)
now
in the weak acid strong base titration
first find the equivalence point
then
the pKa is equal to the pH at half equal equivalence point
3)
at end point
moles of acid = moles of base
so
moles of KHP = moles of NaOH
now
moles = mass /molar mass
so
moles of KHP = 0.6385 / 204
moles of KHP = 3.13 x 10-3
so
moles of NaOH = 3.13 x 10-3
now
given
volume = 33.46 x 10-3 L
now
conc = moles / volume (L)
so
conc of NaOH = 3.13 x 10-3 / 33.46 x 10-3
conc of NaOH = 0.093 M
4)
in this case
mass of uknown = 1 x 35 / 11.5
mass of unknown = 3.04
so
3.04 g of unknown is required
5)
find the second derivative of the curve and equate it to zero
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