sample A: Number of parentatoms 625 Number ofdaughter atoms 19375 sample B: Numb

Question

sample A: Number of parentatoms 625 Number ofdaughter atoms 19375

sample B: Number of parentatoms 100 Number ofdaughter atoms 700

sample C: Number of parentatoms 1000 Number od daughter atoms 3000

1.If you are given that the particular parent isotope used for sample A has a half life of 50 million years, then you know that sample A is ______________ million years old.

2. With a 50-million-year half life, you know that corresponds to sample B being ____________ million years old.

3. Again given that the parent isotope has half live of 50 million years, and knowing the number of half lives elapsed for sample C, you know that sample C is ________ million years old.

Explanation / Answer

age of the smple (t)= (1/lamda)ln(2+N/D)

D= number of daugher atoms

lamda =decay constant

N= remaining number of rasioactibe atoms

1) lamda= 0.693/t1/2 ,

1/lamda =t1/2/0.693

D= 19375

N= 19375-100= 19275

N= (50/0.693)ln(1+100/19275) =0.3733 million years

2 N= (50/0.693)*ln(1+100/600)= 11.12 million years

3. For sample C

life= (50/0.693)*ln(1+1000/2000)=29.25 million yea

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