Question 1: Fructose is a type of sugar found in many different types of fruits,
ID: 887455 • Letter: Q
Question
Question 1: Fructose is a type of sugar found in many different types of fruits, as well as in "high fructose corn syrup," commonly used as sweetener for carbonated beverages. Consider a simplified model of fructose metabolism by the liver (note that fructose is an isomer of glucose, so they both have the same molecular formula): C6H1206 602 6CO2 6H20 The average uptake rate of fructose 50 ug ,the average uptake rate of oxygen -15 ug and the 106 cells h 106 cells h production rate of CO 10 ug Find (A) the limiting reagent, (B) the excess of the other reagent, and (C) the 106 cells h conversion of both reagents. Other relevant information: Molecular Weight (g/mol) Species 180.2 Fructose 32.0 oxygen CO 44.0 18.0 H2OExplanation / Answer
From the given data -
The rate of formation product, CO2 if fructose is a limiting reactant
= (50*10-6 g / 180.2 g/mol) (6 CO2/1 fructose )(44 g/1 mol)
= 73 ug
The rate of formation product, CO2 if O2 is a limiting reactant = (15*10-6 g / 32 g/mol) (6 CO2/6 O2 )(44 g /1 mol)
= 20 ug
From the above calculations we conclude tht O2 is limiting as it is producing less yield.
Therefore, the number of mols of fructose reacts with O2 given
= ((15*10-6 g / 32 g/mol) (1 fructose /6 O2 )(180.2 g/1 mol fructose)
= 14.0 ug
But we have 50 ug fructose initially, therefore, excess reactant left after the reaction = 50 ug - 14 ug = 36 ug
C)
from the reaction the amount of CO2 formed = 10 ug
But theoretically it would be 20 ug
HEnce % yield = 10 ug/20 ug)*100 = 50 %
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.