4.) You have just synthesized a compound that should contain two new non-equival
ID: 886483 • Letter: 4
Question
4.) You have just synthesized a compound that should contain two new non-equivalent hydrogen atoms but the H-NMR signal for those hydrogen atoms gives only a single peak. How might you try to resolve the problem with detecting the signals for the hydrogen atoms?
a.) Use 13C-NMR instead
b.) Cool the sample to very low temperatures
c.) Switch to an H-NMR instrument with a lower magnetic field strength
d.) Nothing can be done to resolve the peaks
5.) Which one of these M+ peaks contains a saturated compound with C, H and a single nitrogen atom?
a.) M+ = 98
b.) M+ = -102
c.) M+ = 113
d.) M+ = 114
Explanation / Answer
Answer –
4) We are given the compound that should contain two new non-equivalent hydrogen atoms but the H-NMR signal for those hydrogen atoms gives only a single peak means the used HNMR instrument with high magnetic field strength, so it is not able to gives two separate peaks. We need to use -NMR instrument with a lower magnetic field strength.
So answer is c.) Switch to an H-NMR instrument with a lower magnetic field strength
5) The saturated compound of the C, H and N is amine. We need to look for such amine that fragmentation gives more stable carbocation and we know the tertiary carbocation is more stable and need to molar mass more than 114, so we can use N-isopropyl-N-methylpropan-2-amine, so when one methyl gets break then it s converted 117 to 102 M+,
so answer is b.) M+ = 102
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