how do you do part C? 2-43. A chemical reaction A B is carried out in a closed v
ID: 885756 • Letter: H
Question
how do you do part C? 2-43. A chemical reaction A B is carried out in a closed vessel. The following data are taken for the concentration of A. CA(g/L.), as a function of time, r(min), from the start of the reaction: amin) r(min) 16 65100160 Ca(pfiter) 0.1823 0.1453 0.1216 0.1025 0.0795 0.0495 A proposed reaction mechanism predicts that Ca and r should be related by the expression CA -CAe CAD CA In ex-c-=-kt where k is the reaction rate constant. (a) Do the data support this prediction? If so, plot the data appropriately to determine the value (b) If the tank volume is 125 L. and there is no B in the tank at t - 0, how much B(g) does the tank ta support this prediction? If so, plot the data appropriately to determine the value of k here is no B in the tank at t = 0, how much B(g) does the tank contain after two hours? (c) Estimate the time required for the final concentration of A to reach 1.1, 1.05, and 1.01 times Che, and determine the mass of B produced at each of these conditions for the reactor describerd in Part (b)Explanation / Answer
ln(CA0 – CAe) / (CA –CAe) = kt
CA0 = 0.1823
CA = 0.1453
CAe = 0.0495
Time = 36 minutes
ln ( 0.1823 – 0.0495) / ( 0.1453 – 0.0495) = k X 36
k X 36 = ln (0.1328 / 0.0958) = ln (1.386) = 0.326
k = 36 / 0.326 = 0.00905
c)
Now let us put the values in the given equation
Time = ln(CA0 – CAe) / (CA –CAe) / k
Time = ln (0.1823 – 0.0495) / ( 1.1 X0.0495 – 0.0495) / k
Time = ln 0.1328 / 0.0495 (1.1-1) / k
Time = ln 0.1328 / 0.0495 X 0.1 / k
Time = ln 0.1328 / 0.00495 / k
Time = 355.16 minutes
Time = ln(CA0 – CAe) / (CA –CAe) / k
Time = ln (0.1823 – 0.0495) / ( 1.05 X0.0495 – 0.0495) / k
Time = ln 0.1328 / 0.0495 (1.05-1) / k
Time = ln 0.1328 / 0.0495 X 0.05 / k
Time = ln 0.1328 / 0.002475 / k
Time = 440.067 minutes
Time = ln(CA0 – CAe) / (CA –CAe) / k
Time = ln (0.1823 – 0.0495) / ( 1.01 X0.0495 – 0.0495) / k
Time = ln 0.1328 / 0.0495 (1.01-1) / k
Time = ln 0.1328 / 0.0495 X 0.01 / k
Time = ln 0.1328 / 0.0000495 / k
Time = 872.33 minutes
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.