Problem 3. (15 Points) Air is passed above an Arnold cell containing liquid tolu

Question

Problem 3. (15 Points) Air is passed above an Arnold cell containing liquid toluene. The temperature is 298 K and the total system pressure of the gas headspace is a constant 1.01 x 10^4 Pa. The cell has a cross-sectional area of 0.8 cm2. a height of 13 cm. and a liquid depth of 3 cm. Using diffusivity data given in Appendix J of W3R. plot the molar flux (mol m^2 s^-1) and the liquid toluene level (cm) vs. time (hr^1). How long does it take for the toluene to be depleted? At 298 K. the vapor pressure and the specific gravity of toluene are 28.4 mm Hg and 0.866. respectively.

Explanation / Answer

Let the gas mixture constitutes 1 mole. Then

            O 2       = 0.07 mol

            CO      = 0.10 mol

            CO 2    = 0.15 mol

            N 2       = 0.68 mol

Molecular weight of the constituents are:

            O 2       = 2 * 16 = 32 g/mol

            CO      = 12 + 16 = 28 g/mol

            CO 2    = 12 + 2 * 16 = 44 g/mol

            N 2       = 2 * 14 = 28 g/mol

Weight of the constituents are: (1 mol of gas mixture)

            O 2       = 0.07 * 32 = 2.24 g

            CO      = 0.10 * 28 = 2.80 g

            CO 2    = 0.15 * 44 = 6.60 g

            N 2       = 0.68 * 28 = 19.04 g

Total weight of gas mixture = 2.24 + 2.80 + 6.60 + 19.04

                                                = 30.68 g

           

           

           

           

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