(A) 1) P 4 + 3O 2 = P 4 O 6 ; H = -1640 kJ and 2) P 4 + 5O 2 = P 4 O 10 ; H = -2

Question

(A) 1) P4 + 3O2 = P4O6; H = -1640 kJ and

2) P4 + 5O2 = P4O10; H = -2940 kJ

then what is the change in enthalpy for the reaction: P4O6 + 2O2 = P4O10? The units are kJ.

(B) Suppose you add 92 ml of dilute acid to 46 ml of water. Both the water and acid were at room temperature (22 C) before being mixed. The temperature of the solution increased to 39 C. How much energy (in kJ) was released by the dissolution of the acid if the specific heat capacity of the solution is still the same as water 4.18 J/(g ·K) and the density was still approximately 1.0 g/ml.

(C)What is the heat capacity of a 10 g sample that has absorbed 100 calories over a temperature range of 30 C in (cal/g(K))? 0.333, 300, 3, 0.666

Thank you

Explanation / Answer

A) the change in enthalpy = (H1 - H2) + H1

                                     = (-1640+2940) -1640 = -340kJ

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