Question 3 The coefficients in a balanced chemical equation provide the mole-to-

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Question 3 The coefficients in a balanced chemical equation provide the mole-to-mole stoichiometry among the reactants and products. The m olar mass (in g/mol) can be used as the conversion factor between moles and the mass of a substance. Thus, the balanced equation and molar masses can be used in conjunction with one another to calculate the masses involved in a reaction incorrect; Try Again; 5 attempts remaining Part C What mass of water is produced from the complete combustion of 4.40x10 3 g of methane? Express your answer with the appropriate units Value Units Submit Hints My Answers Give Up Review Part Part D What mass of oxygen is needed for the complete combustion of 4.40x10 3 g of methane? Express your answer with the appropriate units Value Units Submit Hints My Answers Give Up Review Part

Explanation / Answer

The balanced reaction of methane combustion will be

CH4 + 2O2 --> CO2 + 2H2O

PArt C :

as per stoichiometry of equation

1 mole of CH4 ( molecular weight = 16) will react with 2 moles of O2 ( molecular weight = 32) to give 2 moles of H2O (molecular weight = 18)

so 16 grams of CH4 will react with 64grams of O2 to give 36grams of H2O

so 1 gram of methane will give 36 / 16 grams of H2O

4.4 X 10^-3 grams of methane will give 36 X 4.4 X 10^-3 / 16 grams = 9.9 X 10^-3grams of water

PArt D :

as per stoichiometry of equation

1 mole of CH4 ( molecular weight = 16) will react with 2 moles of O2 ( molecular weight = 32)

so 16 grams of CH4 will react with 64grams of O2

so 1 gram of methane will react with 64 / 16 grams of O2

4.4 X 10^-3 grams of methane will react with 64X 4.4 X 10^-3 / 16 grams = 17.6 X 10^-3 grams of oxygen

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