Here is some Thermodynamics 1) Given the values of H rxn, S rxn, and T below, de
ID: 882631 • Letter: H
Question
Here is some Thermodynamics
1) Given the values of Hrxn, Srxn, and T below, determine Suniv. ( in J/K)
(pay attention to the signs, they aren't all the same equation)
Hrxn= 125 kJ , Srxn= 257 J/K , T= 309 K .
Hrxn= 125 kJ , Srxn= 257 J/K , T= 309 K .
Hrxn= 125 kJ , Srxn= 257 J/K , T= 309 K .
Hrxn= 125 kJ , Srxn= 257 J/K , T= 553 K .
2)Calculate the change in Gibbs free energy for each of the following sets of Hrxn, Srxn, and T.
Hrxn= 128 kJ ; Srxn= 243 J/K ; T= 298 K
Hrxn= 128 kJ ; Srxn= 243 J/K ; T= 298 K
Hrxn= 128 kJ ; Srxn= 243 J/K ; T= 298 K
Hrxn= 128 kJ ; Srxn= 243 J/K ; T= 545 K
Answer all with two sig figs.
3)Calculate the free energy change for the following reaction at 40 C.
C3H8(g)+5O2(g)3CO2(g)+4H2O(g)
Hrxn= -2217 kJ; Srxn= 101.1 J/K.
4)Calculate the free energy change for the reaction at 24 C.
2Ca(s)+O2(g)2CaO(s)
Hrxn= -1269.8 kJ; Srxn= -364.6 J/K
5)The following reaction, calculate Hrxn, Srxn, and Grxn at 25 C.
NH4Cl(s)HCl(g)+NH3(g)
Explanation / Answer
1)
(a)
Hrxn= 125 kJ , Srxn= 257 J/K , T= 309 K .
Ssystem = 257 J/K
Ssurroundings = + H / T
= 125 x 10^2 / 309
= 404.53 J/K
S universe = Ssystem + Ssurroundings
= 257 + 404.53
S universe = 661.53 J/K
(b) Hrxn= 125 kJ , Srxn= 257 J/K , T= 309 K .
Ssystem = 257 J/K
Ssurroundings = - H / T
= -125 x 10^2 / 309
= - 404.53 J/K
S universe = Ssystem + Ssurroundings
= 257 - 404.53
S universe = - 147.53 J/K
(c) Hrxn= 125 kJ , Srxn= 257 J/K , T= 309 K .
Ssystem= 257 J/K
Ssurroundings = + H / T
= +125 x 10^2 / 309
= 404.53 J/K
S universe = Ssystem + Ssurroundings
=- 257 + 404.53
S universe = + 147.53 J/K
(d)
Hrxn= 125 kJ , Srxn= 257 J/K , T= 553 K
Ssystem = - 257 J/K
Ssurroundings = + H / T
= 125 x 10^2 / 553
= 226 J/K
S universe = Ssystem + Ssurroundings
= -257 + 226
S universe = - 30.96 J/K
(2)
(a) Hrxn= 128 kJ ; Srxn= 243 J/K ; T= 298 K
G = H - T S
= -128 - 298 x 243 x 10^-3
G = - 2.0 x 10^2 kJ
(b)Hrxn= 128 kJ ; Srxn= 243 J/K ; T= 298 K
G = H - T S
= 128 + 298 x 243 x 10^-3
G = + 2.0 x 10^2 kJ
(c)Hrxn= 128 kJ ; Srxn= 243 J/K ; T= 298 K
G = H - T S
= -128 + 298 x 243 x 10^-3
G = -56 kJ
(d)
Hrxn= 128 kJ ; Srxn= 243 J/K ; T= 545 K
G = H - T S
= -128 + 545 x 243 x 10^-3
G = 4.4 kJ
(3)
Hrxn= -2217 kJ; Srxn= 101.1 J/K. , T = 40 + 273 = 313 K
G = H - T S
= -2217 - 313 x101.1 x 10^-3
G = - 2248.6 kJ
4)
Hrxn= -1269.8 kJ; Srxn= -364.6 J/K , T = 24 + 273 = 297 K
G = H - T S
= -1269.8 + 297 x 364.6 x 10^-3
G = - 1161.5 kJ
(5)
Horxn = Hoproducts - Horeactants
Sorxn = Soproducts - Soreactants
Go = Ho - T So
please use these three formulas you get answer.
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