in a I. In a coffee cup calorimeter, 50.0 mL of 1.00 M NaOH and 50.0 mL of 1.00

Question

in a I. In a coffee cup calorimeter, 50.0 mL of 1.00 M NaOH and 50.0 mL of 1.00 M HCl are mixed. Both solutions were originally at 24.6 . After the reaction, the final temperature is 31.3 . Given that the density of NaCl solution is 1.038 g/mL and the specific heat of NaCl solution is 3.87 J/g-oC, calculate the AHne /mole for the reaction of HCl with NaOH. Assume that no heat is lost to the surroundings. 2. The molar mass of silver is 108 grams per mole. The specific heat of silver () is 0.28 J/gC. What is the molar heat capacity () of silver? 3. A 0.0100 mole sample of butane was burned in a bomb calorimeter. The heat from the reaction raised the temperature of 1.00 kg of water by 6.90 "C. How much heat was released in this reaction per mole of butane combusted? The specific heat of water is 4.184J/ (g C). 4. The combustion of 0.1584 grams of benzoic acid increases the temperature of a calorimeter by 2.54 °C. Calculate the heat capacity of this calorimeter. The energy released by the com- bustion of benzoic acid is 26.42 k]/gram. 5. Define the following terms; a) exothermic reaction b) endothermic reaction

Explanation / Answer

We can calculate the mass of solution with the help of density and volume

100 ml salt water with density 1.038 g/ml = 103.8 grams of solution

Now

H = mass X specific heat X change in temperature

H = m C dT

H = 103.8 g X 3.87 J/g-C ( 31.3 – 24.6 )

H = 103.8 g X 3.87 J/g-C X 6.7

H = - 2691.4 J

The negative sign indicates that the reaction is exothermic

Now we can calculate the change in enthalpy per mole

So let us find the moles

Moles = molarity X volume = 1 X 0.05 = 0.05 moles

So H in kJ /mole for the reaction of HCl with NaOH will be

- 2691.4 J / 0.05 = -53.82 kJ/mole

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