Please help number 2 and 3A. thanks a lot :) Past-lab Questio 1. Determine how e
ID: 879984 • Letter: P
Question
Please help number 2 and 3A. thanks a lot :)
Explanation / Answer
2 ) 4 Al + 3O2 --------------------> 2 Al2O3
108 g 96g 204 g
5 g ? 9.36g
we need to find out first O2 mass
for 96g O2-----------------------> 204 g Al2O3
??? -----------------------------> 9.36 g Al2O3
O2 weight = 96 x 9.36 / 204
= 4.4 g
Al percentage = (Al mass / total Al2O3 mass ) x 100
= (5 / 9.36 ) x 100
= 53%
O2 percentage = (O2 mass / total Al2O3 mass ) x 100
= (4.4 / 9.36 ) x 100
= 47%
3) Al2O3 weigth = 102 g / mol
Al % = (Al weight / total weight ) x 100
= (2 x 27 / 102 ) x 100
= 53 %
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