3.44 mL of \"Unknown Solution\" were pipetted into a 100 mL volumetric flask alo

Question

3.44 mL of "Unknown Solution" were pipetted into a 100 mL volumetric flask along with the molybdate and nitric acid solutions. This was diluted to volume, mixed and measured in the spectrometer.
The absorbance of this solution was 0.425
The concentration of this solution (from standard plot) was 0.0180 mM
Calculate:
e) Concentration of the unknown solution _______________ mM
f) Concentration of the unknown solution _______________ ppm P

i tried to answer .0017mM and 50.96 but:

For (e) you wrote .018   mM. That is not correct. The error is significant.
For (f) you wrote 50.96   ppm P. That is not correct. The error is significant.
          The AW of Phosphorus is 30.97 ; One phosphate contains one phosphorus.

Explanation / Answer

0.00018 mM

0.03097 ppmP

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