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Safari File Edit View History Bookmarks Window Help 88% Sun 9:31 AM a E ezto.mheducation.com Chemistry question I Chegg.com Your question was answered. Chapter 13 A Vanderbilt Stadium Par Chegg.com Sho 3.11 AM Abigail Looper Chem 1120: Summer 2015 Section O CHEMISTRY een Shot Chapter 13 instructions help 0...3.11 AM Sho X Question 8 (of 20) LE Save & Exit Submit 8.17 AM een Sho 8. 10.000 points 8.17 AM p Chart Exp Chart 1 out of 3 attempts Assistance Be sure to answer all parts. Check My Work Calculate the amount of water (in grams that must be added to each of the following View Hint 570.jpg substances to produce the indicated solution View Qu 3 4670.jpg a) 6.30 g of urea 22 in the preparation of a 21.9 percent by mass solution: CO Question Help Report a Problem 908.jpg (b) 22.2 g of MgCI2 n the preparation of a 6.4 percent mass solution G 4908,jp een Shot Sho 0...0.31 PM .31

Explanation / Answer

Given :

Mass of urea = 6.30 g , mass percent = 21.9

We use following formula:

Mass percent of urea

= (Mass of urea / Mass of solution ) * 100

Lets plug given values

21.9 = (6.30 g/ Mass of solution) * 100

0.219 = (6.30 g / Mass of solution)

Mass of solution = 28.76 g

Mass of water = 28.76 –mass of urea

= 28.76 g – 6.30 g = 22.5 g

Mass of water = 22.5 g

b) Given Mass of MgCl2 = 22.2 g , mass percent= 6.4

Lets use same formula

6.4 = ( 22.2 g MgCl2/ mass of solution )* 100

0.064 = ( 22.2 g MgCl2/ mass of solution )

Mass of solution= 346.875 g

Mass of water = 346.875 g – 22.2 g =324.675 g

Mass of water = 324.675 g

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