Potassium carbonate, K 2 CO 3 , sodium iodide, NaI, magnesium chloride, MgCl 2 ,

Question

Potassium carbonate, K2CO3, sodium iodide, NaI, magnesium chloride, MgCl2, methanol, CH3OH, and ammonium chloride, NH4Cl, are soluble in water. Which produces the largest number of dissolved particles per mole of dissolved solute?

A.  

K2CO3

B.  

NaI

C.  

MgCl2

D.  

CH3OH

E.  

NH4Cl

Potassium carbonate, K2CO3, sodium iodide, NaI, magnesium chloride, MgCl2, methanol, CH3OH, and ammonium chloride, NH4Cl, are soluble in water. Which produces the largest number of dissolved particles per mole of dissolved solute?

Explanation / Answer

answer : MgCl2

explanation : in fact naswer is both MgCl2 and K2CO3 . because on dissoication they both can give 3 ions or particles per mole.

but when we come into actual picture K2CO3 may not completely dissociated . it may has two froms on dissociation

K2CO3 -------------------> K+ + KCO3- it is not completey dissociation.

but in case of MgCl2 it completely dissociate into ions Mg+2 + 2Cl-

A ) K2CO3 -------------------------> 2 K+ + CO3-2    ( 3 particles per mole)

B) NaI ----------------------------> Na+ + I-            ( 2 particles per mole )

C) MgCl2 ------------------------> Mg+2 + 2 Cl- ( 3 particles per mole )

D) CH3OH -----------------------> no ions              ( 0 particles per mole )

E) NH4Cl --------------------------> NH4+ + Cl-       ( 2 particles per mole )

note : if more than one answers are present the answer should be K2CO3 & MgCl2 .

         if only one choice the answer is MgCl2

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.