A 34% Fri 11:53 PM Khaleed Alston a E Chrome File Edit View History Bookmarks Pe

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A 34% Fri 11:53 PM Khaleed Alston a E Chrome File Edit View History Bookmarks People Window Help Khaleed www.saplinglearning.co x M- www.saplinglearning.co x M1 Inbox khaleed.alstone x NY Determine the rate law x DRate Law for a Mechanis x LaGuardia Community C X C www.saplinglearning.com/ibiscms/modibis/view.php?id 1799741 Apps Bookmarks nutrition hing Apt hunting Ch 3rd Grade B Tempeh Recipes Fc Oatmeal food tab 33 Amazing Apartme Other Bookmarks Question 12 of 21 100 100 sapling leaming After 54.0 min, 17.0% of a compound has decomposed. What is the half-life of this reaction assuming first-order kinetics? 10 100 Number min 13 90 95 16 95 17 18 100 19 20 92 A Previous 3 Give Up & View Solution e Check Answer Next d Ext Hin 100

Explanation / Answer

Time, t = 54.0 min

Compound decomposed = 17.0%

It means, final concentration [A]t = 83% of Initial concentration [A]o

[A]t =0.83* [A]o

Step 1. Calculate rate constant of the reaction.

We know that for a first order reaction,

ln([A]t /[A]o) = - k*t

ln(0.83* [A]o / [A]o ) = - k*54

ln(0.83) = - k*54

- 0.1863 = - k*54

k = 3.45X10-3 min-1

Step 2. Calculate half life of the reaction.

Now, half life, t1/2 = 0.693 / k

t1/2 = 0.693 / 3.45X10-3

t1/2 = 200.869 min

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